lainchan / test

#92 testing

Technician · 2017-04-13 12:59
This is a test of the #92. Hopefully we can identify what happens.
The Oracle · 2017-04-13 13:00
>>37 https://images-na.ssl-images-amazon.com/images/G/01/img15/pet-products/small-tiles/23695_pets_vertical_store_dogs_small_tile_8._CB312176604_.jpg
Nanashi No Gombe · 2017-04-18 21:48
test
HELIOS · 2017-04-19 01:55
teeeest
Y.T · 2017-04-20 14:43
>>37 >>>/diy/1 >>>/tech/1
Nameless · 2017-04-20 14:44
>>/diy/1 >>/test/1 >>/Δ/1 >>/Ω/1
Jane Doe · 2017-04-20 14:45
>>>/diy/1 >>>/test/1 >>>/Δ/1 >>>/Ω/1
Motoko Kusanagi · 2017-04-20 14:45
>>/diy/1 >>/tech/1 >>/Δ/1 >>/Ω/1
Neuromancer · 2017-04-20 14:46
>>>/diy/1 >>>/tech/1 >>>/Δ/1 >>>/Ω/1
Mitnick · 2017-04-20 16:46
>>>/diy/1 >>>/tech/1 >>>/Δ/1 >>>/Ω/1
Jean Dupont · 2017-04-20 23:49
>>37 this is a test of autoupdate reported issue test number 1.
Hououin Kyouma · 2017-04-20 23:56
>>37 (OP) this is a test of autoupdate reported issue test number 2.
Dujour · 2017-04-21 00:01
>>37 (OP) (OP) this is a test of autoupdate reported issue test number 3.
Lord Nikon · 2017-04-21 06:53
bitch ass nigga hello <i>hello</i>
Mitnick · 2017-04-23 02:09
def e_step(max_iter=1): count_iter = 0 tol = 0.05 # while np.sum(np.abs(gamma - last_gamma)) > tol and count_iter < max_iter: while count_iter < max_iter: # update tao for i in range(N): for k in range(K): tao[i,k] = pi_est[k] * math.exp(np.dot(ys[i],nu[k]) \ - 0.5 * (gamma[k] + np.dot(nu[k].T,nu[k]))) tao[i,:] = tao[i,:]/(np.sum(tao[i,:]) + .00000001)
Anonymous · 2017-04-23 02:24
testing