lainchan / Δ
I hope this is okay but could you lains pls help me?
The Phantom Phreak · 2017-06-08 06:08
So as the 2 photos show the 7.77v battery (it's a 9 volt that now outputs 7.7 volts) is connected in parallel to the 1.5 battery. Yet I'm not measuring the added volts what am I do wrong?
Case · 2017-06-08 06:09
Less blurry photo
Pris · 2017-06-08 06:11
The actual thing
not_a_snek · 2017-06-08 06:56
you must put the batterie in serial and not parallel.
Be careful to puting it in parallel can overheat the batteries and be quite dangerous !
Incognito · 2017-06-08 06:57
I know drekk about this but I think questions like this are better asked on IRC maybe. Wish I could help you lain.
Nobody important · 2017-06-08 11:39
Put them in series. But.
Your circuit should be designed to work out of actual single 9V battery. If the battery outputs 7.77V, it's pretty much dead and you really shouldn't supply it like this. If you want steady voltage, I recommend buying XL6009 (or anything LM2577 based). It's under a dollar from China.
Batou · 2017-06-08 12:13
>>290
If your battery gives 7.7V it's pretty much drained entirely. You can:
1. Use DC supply from generic 9V charger
2. Buy fresh battery
3. Use 12V battery and regulate it down with LM7809 regulator IC.
3. Use computer PSU regulated with LM7809
4. Change circuitry to use lower voltage
Hope this helps.
Cereal Killer · 2017-06-10 05:37
A 9V battery is not a good source of power at all, anyone who has worked on Arduino project knows it.
I recommend to use AA batteries and a switched-mode power supply (boost converter) to rise the voltage. It is not easy to build one yourself, you need a proper copper board (not breadboard), careful layout and EMI/EMC skills to deal with noise, and solder SMT components manually. But you can get a off-the-shelf circuit board at reasonable price.
Voltage regulators works but has low efficiency.
Agent Smith · 2017-06-28 18:01
>>292
The only reason that didn't result in the AA battery catching fire is because 9v batteries are soykaf to begin with, and that's drained so it won't provide any real current. Please read i bit more on basic electronics.
>>306
This anon gets it. Three AA batteries and a boost converter. I'll just leave this link here, it's a boost converter which accepts as low as 2V (I suppose with greatly reduced current output at higher boost ratios)
https://www.aliexpress.com/item/DC-DC-Adjustable-Boost-Module-2A-Boost-Plate-2A-Step-Up-Module-with-MICRO-USB-2V/32741127985.html
This would not be suitable for high current operations, then listen to >>297, except that instead of a 7809 get a buck converter, which is less than a buck anyway.
Now just my two cents, don't fuarrrking use 9v.
Go 5 or 12 so life will be easy.
Molly Millions · 2017-07-01 07:43
>>293
This. You don't put different voltage sources in parallel. I am confused by your diagram overall.>>293
fenlain · 2017-07-01 08:28
Just use a 9volt battery or just the 7.7.
2 volts wont matter much, most electronics are made to be okay with a range of voltages. DO NOT place un-alike batteries with each other.
Also if u need to drop voktage by 1 to 2 volts use a rectifyer diode. Or investigate a voltage regulator/zener.
Jet Black · 2017-08-03 05:07
hi op here i now got the xl6009ei now i can't get to work i am inputing 4v with 3 series AA batteries but im getting 0 out puts (i do have it connected in a soykafty way.
Haruyoshi · 2017-08-17 22:25
>>290
what the FՍCK is that schematic
Yamaoto Toshi · 2017-08-18 05:51
>>481
According to the datasheet [0], the xl6009 requires at least 5 volts to run properly.
[0] http://www.haoyuelectronics.com/Attachment/XL6009/XL6009-DC-DC-Converter-Datasheet.pdf